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一、问题产生场景

实际项目开发中，需要通过get请求传递一个zip包的地址参数，zip地址中含有特殊字符

二、URL特殊符号及编码十六进制值

Java实现url encoding

import org.apache.http.client.HttpClient;import org.apache.http.client.methods.HttpGet;import java.net.URLEncoder;try {       String url = "http://10.238.6.8:8180/PbDeserialize-service/pbdeserialize/pbfileupdate?pbupdatefile=" + URLEncoder.encode(pbupdatefile, "utf-8");       URI uri = new URI(url);       System.out.println("uri:" + uri);       HttpClient httpClient = null;       HttpGet getMethod = null;       HttpResponse response = null;       getMethod = new HttpGet(uri);       //设置请求头      getMethod.addHeader("Content-Type", "application/json");      getMethod.addHeader("Accept-Encoding", "application/json");      response = httpClient.execute(getMethod);      int statusCode = response.getStatusLine().getStatusCode();      System.out.println("HTTP Status Code:" + statusCode);      if (statusCode != HttpStatus.SC_OK) {            System.out.println("HTTP 请求未成功！HTTP Status Code：" + response.getStatusLine());      }      HttpEntity httpEntity = response.getEntity();      System.out.println("httpEntity:" + httpEntity);      String responseContent = null;      responseContent = EntityUtils.toString(httpEntity, "UTF-8");      //释放资源      EntityUtils.consume(httpEntity);      System.out.println("响应内容: " + responseContent);      } catch (IOException e) {          e.printStackTrace();      } catch (URISyntaxException e) {          e.printStackTrace();      }catch (NullPointerException e){          e.printStackTrace();      }

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